--- id: 56533eb9ac21ba0edf2244aa title: Understanding Uninitialized Variables challengeType: 1 videoUrl: 'https://scrimba.com/c/cBa2JAL' forumTopicId: 18335 --- ## Description
When JavaScript variables are declared, they have an initial value of undefined. If you do a mathematical operation on an undefined variable your result will be NaN which means "Not a Number". If you concatenate a string with an undefined variable, you will get a literal string of "undefined".
## Instructions
Initialize the three variables a, b, and c with 5, 10, and "I am a" respectively so that they will not be undefined.
## Tests
```yml tests: - text: a should be defined and evaluated to have the value of 6. testString: assert(typeof a === 'number' && a === 6); - text: b should be defined and evaluated to have the value of 15. testString: assert(typeof b === 'number' && b === 15); - text: c should not contain undefined and should have a value of "I am a String!" testString: assert(!/undefined/.test(c) && c === "I am a String!"); - text: You should not change code below the specified comment. testString: assert(/a = a \+ 1;/.test(code) && /b = b \+ 5;/.test(code) && /c = c \+ " String!";/.test(code)); ```
## Challenge Seed
```js // Only change code below this line var a; var b; var c; // Only change code above this line a = a + 1; b = b + 5; c = c + " String!"; ```
### After Test
```js (function(a,b,c){ return "a = " + a + ", b = " + b + ", c = '" + c + "'"; })(a,b,c); ```
## Solution
```js var a = 5; var b = 10; var c = "I am a"; a = a + 1; b = b + 5; c = c + " String!"; ```