--- id: 5900f3781000cf542c50fe8b challengeType: 5 title: 'Problem 12: Highly divisible triangular number' forumTopicId: 301746 --- ## Description
The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
Let us list the factors of the first seven triangle numbers:
1: 1
3: 1, 3
6: 1, 2, 3, 6
10: 1, 2, 5, 10
15: 1, 3, 5, 15
21: 1, 3, 7, 21
28: 1, 2, 4, 7, 14, 28
We can see that 28 is the first triangle number to have over five divisors. What is the value of the first triangle number to have over `n` divisors?
## Instructions
## Tests
```yml tests: - text: divisibleTriangleNumber(5) should return a number. testString: assert(typeof divisibleTriangleNumber(5) === 'number'); - text: divisibleTriangleNumber(5) should return 28. testString: assert.strictEqual(divisibleTriangleNumber(5), 28); - text: divisibleTriangleNumber(23) should return 630. testString: assert.strictEqual(divisibleTriangleNumber(23), 630); - text: divisibleTriangleNumber(167) should return 1385280. testString: assert.strictEqual(divisibleTriangleNumber(167), 1385280); - text: divisibleTriangleNumber(374) should return 17907120. testString: assert.strictEqual(divisibleTriangleNumber(374), 17907120); - text: divisibleTriangleNumber(500) should return 76576500. testString: assert.strictEqual(divisibleTriangleNumber(500), 76576500); ```
## Challenge Seed
```js function divisibleTriangleNumber(n) { return true; } divisibleTriangleNumber(500); ```
## Solution
```js function divisibleTriangleNumber(n) { if (n === 1) return 3; let counter = 1; let triangleNumber = counter++; while (noOfFactors(triangleNumber) < n) { triangleNumber += counter++; } return triangleNumber; } function noOfFactors(num) { const primeFactors = getPrimeFactors(num); let prod = 1; for(let p in primeFactors) { prod *= (primeFactors[p] + 1) } return prod; } function getPrimeFactors(num) { let n = num; let primes = {}; let p = 2; let sqrt = Math.sqrt(num); function checkAndUpdate(inc) { if (n % p === 0) { const curr = primes[p]; if (curr) { primes[p]++ } else { primes[p] = 1; } n /= p; } else { p += inc; } } while(p === 2 && p <= n) { checkAndUpdate(1); } while (p <= n && p <= sqrt) { checkAndUpdate(2); } if(Object.keys(primes).length === 0) { primes[num] = 1; } else if(n !== 1) { primes[n] = 1; } return primes; } ```