--- id: 5900f4711000cf542c50ff84 challengeType: 5 title: 'Problem 261: Pivotal Square Sums' forumTopicId: 301910 --- ## Description
Let us call a positive integer k a square-pivot, if there is a pair of integers m > 0 and n ≥ k, such that the sum of the (m+1) consecutive squares up to k equals the sum of the m consecutive squares from (n+1) on: (k-m)2 + ... + k2 = (n+1)2 + ... + (n+m)2. Some small square-pivots are 4: 32 + 42 = 52 21: 202 + 212 = 292 24: 212 + 222 + 232 + 242 = 252 + 262 + 272 110: 1082 + 1092 + 1102 = 1332 + 1342Find the sum of all distinct square-pivots ≤ 1010.
## Instructions
## Tests
```yml tests: - text: euler261() should return 238890850232021. testString: assert.strictEqual(euler261(), 238890850232021); ```
## Challenge Seed
```js function euler261() { return true; } euler261(); ```
## Solution
```js // solution required ```