--- id: 5900f38b1000cf542c50fe9e challengeType: 5 title: 'Problem 31: Coin sums' forumTopicId: 301965 --- ## Description
In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:
1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).
It is possible to make £2 in the following way:
1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
How many different ways can `n` pence be made using any number of coins?
## Instructions
## Tests
```yml tests: - text: coinSums(50) should return a number. testString: assert(typeof coinSums(50) === 'number'); - text: coinSums(50) should return 451. testString: assert(coinSums(50) == 451); - text: coinSums(100) should return 4563. testString: assert(coinSums(100) == 4563); - text: coinSums(150) should return 21873. testString: assert(coinSums(150) == 21873); - text: coinSums(200) should return 73682. testString: assert(coinSums(200) == 73682); ```
## Challenge Seed
```js function coinSums(n) { return n; } coinSums(200); ```
## Solution
```js const coinSums = (n) => { const getWays = (n, m=8, c=[1, 2, 5, 10, 20, 50, 100, 200]) => { if (n === 0) return 1; if (m === 0 || n < 0) return 0; return getWays(n - c[m - 1], m, c) + getWays(n, m - 1, c); }; return getWays(n); }; ```