--- id: 5900f3b11000cf542c50fec4 challengeType: 5 title: 'Problem 69: Totient maximum' forumTopicId: 302181 --- ## Description
Euler's Totient function, φ(n) [sometimes called the phi function], is used to determine the number of numbers less than n which are relatively prime to n. For example, as 1, 2, 4, 5, 7, and 8, are all less than nine and relatively prime to nine, φ(9)=6.
|n|Relatively Prime|φ(n)|n/φ(n)| |--- |--- |--- |--- | |2|1|1|2| |3|1,2|2|1.5| |4|1,3|2|2| |5|1,2,3,4|4|1.25| |6|1,5|2|3| |7|1,2,3,4,5,6|6|1.1666...| |8|1,3,5,7|4|2| |9|1,2,4,5,7,8|6|1.5| |10|1,3,7,9|4|2.5|
It can be seen that n=6 produces a maximum n/φ(n) for n ≤ 10. Find the value of n ≤ 1,000,000 for which n/φ(n) is a maximum.
## Instructions
## Tests
```yml tests: - text: totientMaximum() should return a number. testString: assert(typeof totientMaximum() === 'number'); - text: totientMaximum() should return 510510. testString: assert.strictEqual(totientMaximum(), 510510); ```
## Challenge Seed
```js function totientMaximum() { return true; } totientMaximum(); ```
## Solution
```js // solution required ```