---
title: Use Destructuring Assignment to Pass an Object as a Function's Parameters
---
## Use Destructuring Assignment to Pass an Object as a Function's Parameters

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You could pass the entire object, and then pick the specific attributes you want by using the `.` operator. But ES6 offers a more elegant option!

## Hint 1:

Get rid of the `stats`, and see if you can destructure it. We need the `max` and `min` of `stats`.

## Spoiler Warning - Solutions Ahead!

## Solution 1:

```javascript
const half = (function() {
  "use strict"; // do not change this line

  // change code below this line
  return function half({max, min}) {
    // use function argument destructuring
    return (max + min) / 2.0;
  };
  // change code above this line

})();
```

Notice that we are destructuring `stats` to pass two of its attributes - `max` and `min` - to the function. Don't forget to the modify the second return statement. Change `stats.max` to just `max`, and change `stats.min` to just `min`.

## Solution 2:

Here is another solution that works. Not much of a difference, other than the fact that the function doesn't have a name.

```javascript
const half = (function() {
  "use strict"; // do not change this line

  // change code below this line
  return (({max, min}) => {
    // use function argument destructuring
    return (max + min) / 2.0;
  });
  // change code above this line

})();
```