--- id: 5900f4b71000cf542c50ffca challengeType: 5 title: 'Problem 331: Cross flips' --- ## Description
N×N disks are placed on a square game board. Each disk has a black side and white side. At each turn, you may choose a disk and flip all the disks in the same row and the same column as this disk: thus 2×N-1 disks are flipped. The game ends when all disks show their white side. The following example shows a game on a 5×5 board. It can be proven that 3 is the minimal number of turns to finish this game. The bottom left disk on the N×N board has coordinates (0,0); the bottom right disk has coordinates (N-1,0) and the top left disk has coordinates (0,N-1). Let CN be the following configuration of a board with N×N disks: A disk at (x,y) satisfying , shows its black side; otherwise, it shows its white side. C5 is shown above. Let T(N) be the minimal number of turns to finish a game starting from configuration CN or 0 if configuration CN is unsolvable. We have shown that T(5)=3. You are also given that T(10)=29 and T(1 000)=395253. Find .
## Instructions
## Tests
```yml tests: - text: euler331() should return 467178235146843500. testString: assert.strictEqual(euler331(), 467178235146843500, 'euler331() should return 467178235146843500.'); ```
## Challenge Seed
```js function euler331() { // Good luck! return true; } euler331(); ```
## Solution
```js // solution required ```