--- id: 5900f4761000cf542c50ff88 title: 'Problem 265: Binary Circles' challengeType: 5 forumTopicId: 301914 dashedName: problem-265-binary-circles --- # --description-- $2^N$ binary digits can be placed in a circle so that all the $N$-digit clockwise subsequences are distinct. For $N = 3$, two such circular arrangements are possible, ignoring rotations: two circular arrangements for N = 3 For the first arrangement, the 3-digit subsequences, in clockwise order, are: 000, 001, 010, 101, 011, 111, 110 and 100. Each circular arrangement can be encoded as a number by concatenating the binary digits starting with the subsequence of all zeros as the most significant bits and proceeding clockwise. The two arrangements for $N = 3$ are thus represented as 23 and 29: $${00010111}_2 = 23\\\\ {00011101}_2 = 29$$ Calling $S(N)$ the sum of the unique numeric representations, we can see that $S(3) = 23 + 29 = 52$. Find $S(5)$. # --hints-- `binaryCircles()` should return `209110240768`. ```js assert.strictEqual(binaryCircles(), 209110240768); ``` # --seed-- ## --seed-contents-- ```js function binaryCircles() { return true; } binaryCircles(); ``` # --solutions-- ```js // solution required ```