--- id: 587d8254367417b2b2512c6f title: Perform a Subset Check on Two Sets of Data challengeType: 1 --- ## Description
In this exercise we are going to perform a subset test on 2 sets of data. We will create a method on our Set data structure called subset. This will compare the first set, against the second and if the first set is fully contained within the Second then it will return true. For example, if setA = ['a','b'] and setB = ['a','b','c','d'], then the subset of setA and setB is: setA.subset(setB) should be true.
## Instructions
## Tests
```yml tests: - text: Your Set class should have a union method. testString: assert((function(){var test = new Set(); return (typeof test.subset === 'function')})(), 'Your Set class should have a union method.'); - text: The first Set() was contained in the second Set testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setB.add('b'); setB.add('c'); setB.add('a'); setB.add('d'); var subsetSetAB = setA.subset(setB);return (subsetSetAB === true)})(), 'The first Set() was contained in the second Set'); - text: ['a', 'b'].subset(['a', 'b', 'c', 'd']) should return true") testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('a'); setB.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)})(), "['a', 'b'].subset(['a', 'b', 'c', 'd']) should return true"); - text: ['a', 'b', 'c'].subset(['a', 'b']) should return false") testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('a'); setB.add('b'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)})(), "['a', 'b', 'c'].subset(['a', 'b']) should return false"); - text: [].subset([]) should return true testString: assert((function(){var setA = new Set(); var setB = new Set(); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)})(), '[].subset([]) should return true'); - text: ['a', 'b'].subset(['c', 'd']) should return false") testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)})(), "['a', 'b'].subset(['c', 'd']) should return false"); ```
## Challenge Seed
```js function Set() { // the var collection will hold the set var collection = []; // this method will check for the presence of an element and return true or false this.has = function(element) { return (collection.indexOf(element) !== -1); }; // this method will return all the values in the set this.values = function() { return collection; }; // this method will add an element to the set this.add = function(element) { if(!this.has(element)){ collection.push(element); return true; } return false; }; // this method will remove an element from a set this.remove = function(element) { if(this.has(element)){ var index = collection.indexOf(element); collection.splice(index,1); return true; } return false; }; // this method will return the size of the collection this.size = function() { return collection.length; }; // this method will return the union of two sets this.union = function(otherSet) { var unionSet = new Set(); var firstSet = this.values(); var secondSet = otherSet.values(); firstSet.forEach(function(e){ unionSet.add(e); }); secondSet.forEach(function(e){ unionSet.add(e); }); return unionSet; }; // this method will return the intersection of two sets as a new set this.intersection = function(otherSet) { var intersectionSet = new Set(); var firstSet = this.values(); firstSet.forEach(function(e){ if(otherSet.has(e)){ intersectionSet.add(e); } }); return intersectionSet; }; // this method will return the difference of two sets as a new set this.difference = function(otherSet) { var differenceSet = new Set(); var firstSet = this.values(); firstSet.forEach(function(e){ if(!otherSet.has(e)){ differenceSet.add(e); } }); return differenceSet; }; // change code below this line // change code above this line } ```
## Solution
```js function Set() {var collection = []; this.has = function(e){return(collection.indexOf(e) !== -1);};this.values = function() {return collection;};this.add = function(element) {if (!this.has(element)) {collection.push(element);return true;} else {return false;}};this.remove = function(element) {if(this.has(element)) {var i = collection.indexOf(element);collection.splice(i, 1);return true;}return false;};this.size = function() {return collection.length;};this.union = function(set) {var u = new Set();var c = this.values();var s = set.values();c.forEach(function(element){u.add(element);});s.forEach(function(element){u.add(element);});return u;};this.intersection = function(set) {var i = new Set();var c = this.values();c.forEach(function(element){if(s.has(element)) i.add(element);});};this.difference = function(set) {var d = new Set();var c = this.values();c.forEach(function(e){if(!set.has(e)) d.add(e);});};this.subset = function(set) {var isSubset = true;var c = this.values();c.forEach(function(e){if(!set.has(e)) isSubset = false;});return isSubset;};} ```