--- id: 5900f39e1000cf542c50feb1 challengeType: 5 title: 'Problem 50: Consecutive prime sum' videoUrl: '' localeTitle: 问题50:连续的总和 --- ## Description
素数41可以写成六个连续素数的总和:41 = 2 + 3 + 5 + 7 + 11 + 13这是连续素数的最长和,它加到低于一百的素数。连续素数低于1000的连续素数加上一个素数,包含21个项,等于953.哪个素数低于一百万,可以写成最连续素数的总和?
## Instructions
## Tests
```yml tests: - text: consecutivePrimeSum(1000)应该返回953。 testString: 'assert.strictEqual(consecutivePrimeSum(1000), 953, "consecutivePrimeSum(1000) should return 953.");' - text: consecutivePrimeSum(1000000)应该返回997651。 testString: 'assert.strictEqual(consecutivePrimeSum(1000000), 997651, "consecutivePrimeSum(1000000) should return 997651.");' ```
## Challenge Seed
```js function consecutivePrimeSum(limit) { // Good luck! return true; } consecutivePrimeSum(1000000); ```
## Solution
```js // solution required ```