--- id: 599d0ba974141b0f508b37d5 title: Emirp primes challengeType: 5 forumTopicId: 302253 dashedName: emirp-primes --- # --description-- An emirp (**prime** spelled backwards) are primes that when reversed (in their decimal representation) are a different prime. # --instructions-- Write a function that: The function should accept two parameters. The first will receive `n` or the range as an array. The second will receive a boolean, that specifies if the function returns the emirps as an array or a single number (the number of primes in the range or the nth prime). According to the parameters the function should return an array or a number. # --hints-- `emirps` should be a function. ```js assert(typeof emirps === 'function'); ``` `emirps(20,true)` should return `[13,17,31,37,71,73,79,97,107,113,149,157,167,179,199,311,337,347,359,389]` ```js assert.deepEqual(emirps(20, true), [ 13, 17, 31, 37, 71, 73, 79, 97, 107, 113, 149, 157, 167, 179, 199, 311, 337, 347, 359, 389 ]); ``` `emirps(1000)` should return `70529` ```js assert.deepEqual(emirps(1000), 70529); ``` `emirps([7700,8000],true)` should return `[7717,7757,7817,7841,7867,7879,7901,7927,7949,7951,7963]` ```js assert.deepEqual(emirps([7700, 8000], true), [ 7717, 7757, 7817, 7841, 7867, 7879, 7901, 7927, 7949, 7951, 7963 ]); ``` `emirps([7700,8000],false)` should return `11` ```js assert.deepEqual(emirps([7700, 8000], false), 11); ``` # --seed-- ## --seed-contents-- ```js function emirps(n) { } ``` # --solutions-- ```js function emirps(num, showEmirps) { const is_prime = function(n) { if (!(n % 2) || !(n % 3)) return false; let p = 1; while (p * p < n) { if (n % (p += 4) == 0 || n % (p += 2) == 0) { return false; } } return true; }; const is_emirp = function(n) { const r = parseInt(n.toString().split('').reverse().join('')); return r != n && is_prime(n) && is_prime(r); }; let i, arr = []; if (typeof num === 'number') { for (i = 0; arr.length < num; i++) if (is_emirp(i)) arr.push(i); // first x emirps if (showEmirps) return arr; // xth emirp return arr.pop(); } if (Array.isArray(num)) { for (i = num[0]; i <= num[1]; i++) if (is_emirp(i)) arr.push(i); // emirps between x .. y if (showEmirps) return arr; // number of emirps between x .. y return arr.length; } } ```