--- id: 56533eb9ac21ba0edf2244e1 title: Nesting For Loops challengeType: 1 videoUrl: 'https://scrimba.com/c/cRn6GHM' forumTopicId: 18248 --- ## Description
If you have a multi-dimensional array, you can use the same logic as the prior waypoint to loop through both the array and any sub-arrays. Here is an example: ```js var arr = [ [1,2], [3,4], [5,6] ]; for (var i=0; i < arr.length; i++) { for (var j=0; j < arr[i].length; j++) { console.log(arr[i][j]); } } ``` This outputs each sub-element in arr one at a time. Note that for the inner loop, we are checking the .length of arr[i], since arr[i] is itself an array.
## Instructions
Modify function multiplyAll so that it multiplies the product variable by each number in the sub-arrays of arr
## Tests
```yml tests: - text: multiplyAll([[1],[2],[3]]) should return 6 testString: assert(multiplyAll([[1],[2],[3]]) === 6); - text: multiplyAll([[1,2],[3,4],[5,6,7]]) should return 5040 testString: assert(multiplyAll([[1,2],[3,4],[5,6,7]]) === 5040); - text: multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]]) should return 54 testString: assert(multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]]) === 54); ```
## Challenge Seed
```js function multiplyAll(arr) { var product = 1; // Only change code below this line // Only change code above this line return product; } // Modify values below to test your code multiplyAll([[1,2],[3,4],[5,6,7]]); ```
## Solution
```js function multiplyAll(arr) { var product = 1; for (var i = 0; i < arr.length; i++) { for (var j = 0; j < arr[i].length; j++) { product *= arr[i][j]; } } return product; } multiplyAll([[1,2],[3,4],[5,6,7]]); ```