--- id: 5900f41a1000cf542c50ff2d title: >- Problem 174: Counting the number of "hollow" square laminae that can form one, two, three, ... distinct arrangements challengeType: 5 forumTopicId: 301809 dashedName: >- problem-174-counting-the-number-of-hollow-square-laminae-that-can-form-one-two-three-----distinct-arrangements --- # --description-- We shall define a square lamina to be a square outline with a square "hole" so that the shape possesses vertical and horizontal symmetry. Given eight tiles it is possible to form a lamina in only one way: 3x3 square with a 1x1 hole in the middle. However, using thirty-two tiles it is possible to form two distinct laminae. two square lamina with holes 2x2 and 7x7 If $t$ represents the number of tiles used, we shall say that $t = 8$ is type $L(1)$ and $t = 32$ is type $L(2)$. Let $N(n)$ be the number of $t ≤ 1000000$ such that $t$ is type $L(n)$; for example, $N(15) = 832$. What is $\sum N(n)$ for $1 ≤ n ≤ 10$? # --hints-- `hollowSquareLaminaeDistinctArrangements()` should return `209566`. ```js assert.strictEqual(hollowSquareLaminaeDistinctArrangements(), 209566); ``` # --seed-- ## --seed-contents-- ```js function hollowSquareLaminaeDistinctArrangements() { return true; } hollowSquareLaminaeDistinctArrangements(); ``` # --solutions-- ```js // solution required ```