--- id: 5900f43c1000cf542c50ff4e challengeType: 5 title: 'Problem 207: Integer partition equations' forumTopicId: 301848 --- ## Description
For some positive integers k, there exists an integer partition of the form   4t = 2t + k, where 4t, 2t, and k are all positive integers and t is a real number. The first two such partitions are 41 = 21 + 2 and 41.5849625... = 21.5849625... + 6. Partitions where t is also an integer are called perfect. For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with k ≤ m. Thus P(6) = 1/2. In the following table are listed some values of P(m)    P(5) = 1/1    P(10) = 1/2    P(15) = 2/3    P(20) = 1/2    P(25) = 1/2    P(30) = 2/5    ...    P(180) = 1/4    P(185) = 3/13 Find the smallest m for which P(m) < 1/12345
## Instructions
## Tests
```yml tests: - text: euler207() should return 44043947822. testString: assert.strictEqual(euler207(), 44043947822); ```
## Challenge Seed
```js function euler207() { // Good luck! return true; } euler207(); ```
## Solution
```js // solution required ```