--- id: 5900f3a61000cf542c50feb9 challengeType: 5 title: 'Problem 58: Spiral primes' forumTopicId: 302169 --- ## Description
Starting with 1 and spiralling anticlockwise in the following way, a square spiral with side length 7 is formed. 37 36 35 34 33 32 31 38 17 16 15 14 13 30 39 18  5  4  3 12 29 40 19  6  1  2 11 28 41 20  7  8  9 10 27 42 21 22 23 24 25 2643 44 45 46 47 48 49 It is interesting to note that the odd squares lie along the bottom right diagonal, but what is more interesting is that 8 out of the 13 numbers lying along both diagonals are prime; that is, a ratio of 8/13 ≈ 62%. If one complete new layer is wrapped around the spiral above, a square spiral with side length 9 will be formed. If this process is continued, what is the side length of the square spiral for which the ratio of primes along both diagonals first falls below 10%?
## Instructions
## Tests
```yml tests: - text: euler58() should return 26241. testString: assert.strictEqual(euler58(), 26241); ```
## Challenge Seed
```js function euler58() { // Good luck! return true; } euler58(); ```
## Solution
```js // solution required ```