--- id: 587d7dab367417b2b2512b70 title: Introduction to Currying and Partial Application challengeType: 1 --- ## Description
The arity of a function is the number of arguments it requires. Currying a function means to convert a function of N arity into N functions of arity 1. In other words, it restructures a function so it takes one argument, then returns another function that takes the next argument, and so on. Here's an example: ```js //Un-curried function function unCurried(x, y) { return x + y; } //Curried function function curried(x) { return function(y) { return x + y; } } //Alternative using ES6 const curried = x => y => x + y curried(1)(2) // Returns 3 ``` This is useful in your program if you can't supply all the arguments to a function at one time. You can save each function call into a variable, which will hold the returned function reference that takes the next argument when it's available. Here's an example using the curried function in the example above: ```js // Call a curried function in parts: var funcForY = curried(1); console.log(funcForY(2)); // Prints 3 ``` Similarly, partial application can be described as applying a few arguments to a function at a time and returning another function that is applied to more arguments. Here's an example: ```js //Impartial function function impartial(x, y, z) { return x + y + z; } var partialFn = impartial.bind(this, 1, 2); partialFn(10); // Returns 13 ```
## Instructions
Fill in the body of the add function so it uses currying to add parameters x, y, and z.
## Tests
```yml tests: - text: add(10)(20)(30) should return 60. testString: assert(add(10)(20)(30) === 60, 'add(10)(20)(30) should return 60.'); - text: add(1)(2)(3) should return 6. testString: assert(add(1)(2)(3) === 6, 'add(1)(2)(3) should return 6.'); - text: add(11)(22)(33) should return 66. testString: assert(add(11)(22)(33) === 66, 'add(11)(22)(33) should return 66.'); - text: Your code should include a final statement that returns x + y + z. testString: assert(code.match(/[xyz]\s*?\+\s*?[xyz]\s*?\+\s*?[xyz]/g), 'Your code should include a final statement that returns x + y + z.'); ```
## Challenge Seed
```js function add(x) { // Add your code below this line // Add your code above this line } add(10)(20)(30); ```
## Solution
```js const add = x => y => z => x + y + z ```