--- id: 5900f3c51000cf542c50fed6 title: 'Problem 88: Product-sum numbers' challengeType: 5 forumTopicId: 302203 dashedName: problem-88-product-sum-numbers --- # --description-- A natural number, N, that can be written as the sum and product of a given set of at least two natural numbers, {`a`1, `a`2, ... , `a`k} is called a product-sum number: N = `a`1 + `a`2 + ... + `a`k = `a`1 × `a`2 × ... × `a`k. For example, 6 = 1 + 2 + 3 = 1 × 2 × 3. For a given set of size, `k`, we shall call the smallest N with this property a minimal product-sum number. The minimal product-sum numbers for sets of size, `k` = 2, 3, 4, 5, and 6 are as follows.
k=2: 4 = 2 × 2 = 2 + 2
k=3: 6 = 1 × 2 × 3 = 1 + 2 + 3
k=4: 8 = 1 × 1 × 2 × 4 = 1 + 1 + 2 + 4
k=5: 8 = 1 × 1 × 2 × 2 × 2 = 1 + 1 + 2 + 2 + 2
k=6: 12 = 1 × 1 × 1 × 1 × 2 × 6 = 1 + 1 + 1 + 1 + 2 + 6
Hence for 2≤`k`≤6, the sum of all the minimal product-sum numbers is 4+6+8+12 = 30; note that 8 is only counted once in the sum. In fact, as the complete set of minimal product-sum numbers for 2≤`k`≤12 is {4, 6, 8, 12, 15, 16}, the sum is 61. What is the sum of all the minimal product-sum numbers for 2≤`k`≤12000? # --hints-- `productSumNumbers()` should return a number. ```js assert(typeof productSumNumbers() === 'number'); ``` `productSumNumbers()` should return 7587457. ```js assert.strictEqual(productSumNumbers(), 7587457); ``` # --seed-- ## --seed-contents-- ```js function productSumNumbers() { return true; } productSumNumbers(); ``` # --solutions-- ```js // solution required ```