--- title: Exponential Search localeTitle: 指数搜索 --- ## 指数搜索 指数搜索也称为手指搜索,通过每次迭代跳过`2^i`元素来搜索排序数组中的元素,其中i表示 循环控制变量的值,然后验证在最后一次跳转和当前跳转之间是否存在搜索元素 # 复杂性最坏的情况 为O(log(N)) 由于名称经常混淆,因此算法的命名不是因为时间复杂性。 该名称是由于算法跳过具有等于2的指数的步骤的元素而产生的 # 作品 1. 一次跳转数组`2^i`元素,搜索条件`Array[2^(i-1)] < valueWanted < Array[2^i]` 。如果`2^i`大于数组的长度,则将上限设置为数组的长度。 2. 在`Array[2^(i-1)]`和`Array[2^i]`之间进行二进制搜索 # 码 ``` // C++ program to find an element x in a // sorted array using Exponential search. #include using namespace std; int binarySearch(int arr[], int, int, int); // Returns position of first ocurrence of // x in array int exponentialSearch(int arr[], int n, int x) { // If x is present at firt location itself if (arr[0] == x) return 0; // Find range for binary search by // repeated doubling int i = 1; while (i < n && arr[i] <= x) i = i*2; // Call binary search for the found range. return binarySearch(arr, i/2, min(i, n), x); } // A recursive binary search function. It returns // location of x in given array arr[l..r] is // present, otherwise -1 int binarySearch(int arr[], int l, int r, int x) { if (r >= l) { int mid = l + (r - l)/2; // If the element is present at the middle // itself if (arr[mid] == x) return mid; // If element is smaller than mid, then it // can only be present n left subarray if (arr[mid] > x) return binarySearch(arr, l, mid-1, x); // Else the element can only be present // in right subarray return binarySearch(arr, mid+1, r, x); } // We reach here when element is not present // in array return -1; } int main(void) { int arr[] = {2, 3, 4, 10, 40}; int n = sizeof(arr)/ sizeof(arr[0]); int x = 10; int result = exponentialSearch(arr, n, x); (result == -1)? printf("Element is not present in array") : printf("Element is present at index %d", result); return 0; } ``` # 更多信息 * [维基百科](https://en.wikipedia.org/wiki/Exponential_search) * [GeeksForGeeks](https://www.geeksforgeeks.org/exponential-search/) # 积分 [C ++实现](https://www.wikitechy.com/technology/exponential-search/)