---
id: 5900f3a01000cf542c50feb3
challengeType: 5
title: 'Problem 52: Permuted multiples'
---
## Description
It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x, and 6x, contain the same digits.
## Instructions
## Tests
```yml
tests:
- text: permutedMultiples() should return 142857.
testString: 'assert.strictEqual(permutedMultiples(), 142857, "permutedMultiples() should return 142857.");'
```
## Challenge Seed
```js
function permutedMultiples() {
// Good luck!
return true;
}
permutedMultiples();
```
## Solution
```js
function permutedMultiples() {
const isPermutation = (a, b) =>
a.length !== b.length
? false
: a.split('').sort().join() === b.split('').sort().join();
let start = 1;
let found = false;
let result = 0;
while (!found) {
start *= 10;
for (let i = start; i < start * 10 / 6; i++) {
found = true;
for (let j = 2; j <= 6; j++) {
if (!isPermutation(i + ", j * i + ")) {
found = false;
break;
}
}
if (found) {
result = i;
break;
}
}
}
return result;
}
```