--- title: Euler method id: 59880443fb36441083c6c20e challengeType: 5 --- ## Description

Euler's method numerically approximates solutions of first-order ordinary differential equations (ODEs) with a given initial value. It is an explicit method for solving initial value problems (IVPs), as described in the wikipedia page.

The ODE has to be provided in the following form:

:: $\frac{dy(t)}{dt} = f(t,y(t))$

with an initial value

:: $y(t_0) = y_0$

To get a numeric solution, we replace the derivative on the LHS with a finite difference approximation:

:: $\frac{dy(t)}{dt} \approx \frac{y(t+h)-y(t)}{h}$

then solve for $y(t+h)$:

:: $y(t+h) \approx y(t) + h \, \frac{dy(t)}{dt}$

which is the same as

:: $y(t+h) \approx y(t) + h \, f(t,y(t))$

The iterative solution rule is then:

:: $y_{n+1} = y_n + h \, f(t_n, y_n)$

where $h$ is the step size, the most relevant parameter for accuracy of the solution. A smaller step size increases accuracy but also the computation cost, so it has always has to be hand-picked according to the problem at hand.

Example: Newton's Cooling Law

Newton's cooling law describes how an object of initial temperature $T(t_0) = T_0$ cools down in an environment of temperature $T_R$:

:: $\frac{dT(t)}{dt} = -k \, \Delta T$

or

:: $\frac{dT(t)}{dt} = -k \, (T(t) - T_R)$

It says that the cooling rate $\frac{dT(t)}{dt}$ of the object is proportional to the current temperature difference $\Delta T = (T(t) - T_R)$ to the surrounding environment.

The analytical solution, which we will compare to the numerical approximation, is

:: $T(t) = T_R + (T_0 - T_R) \; e^{-k t}$

Task:

Implement a routine of Euler's method and then to use it to solve the given example of Newton's cooling law with it for three different step sizes of:

::* 2 s

::* 5 s and

::* 10 s

and to compare with the analytical solution.

Initial values:

::* initial temperature $T_0$ shall be 100 °C

::* room temperature $T_R$ shall be 20 °C

::* cooling constant $k$ shall be 0.07

::* time interval to calculate shall be from 0 s ──► 100 s

## Instructions
## Tests
```yml tests: - text: eulersMethod is a function. testString: assert(typeof eulersMethod === 'function', 'eulersMethod is a function.'); - text: eulersMethod(0, 100, 100, 10) should return a number. testString: assert(typeof eulersMethod(0, 100, 100, 10) === 'number', 'eulersMethod(0, 100, 100, 10) should return a number.'); - text: eulersMethod(0, 100, 100, 10) should return 20.0424631833732. testString: assert.equal(eulersMethod(0, 100, 100, 2), 20.0424631833732, 'eulersMethod(0, 100, 100, 10) should return 20.0424631833732.'); - text: eulersMethod(0, 100, 100, 10) should return 20.01449963666907. testString: assert.equal(eulersMethod(0, 100, 100, 5), 20.01449963666907, 'eulersMethod(0, 100, 100, 10) should return 20.01449963666907.'); - text: eulersMethod(0, 100, 100, 10) should return 20.000472392. testString: assert.equal(eulersMethod(0, 100, 100, 10), 20.000472392, 'eulersMethod(0, 100, 100, 10) should return 20.000472392.'); ```
## Challenge Seed
```js function eulersMethod (x1, y1, x2, h) { // Good luck! } ```
## Solution
```js function eulersMethod(x1, y1, x2, h) { let x = x1; let y = y1; while ((x < x2 && x1 < x2) || (x > x2 && x1 > x2)) { y += h * (-0.07 * (y - 20)); x += h; } return y; } ```