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id	title	challengeType	forumTopicId	dashedName
a9bd25c716030ec90084d8a1	Dividir e agrupar arrays	1	16005	chunky-monkey

--description--

Escreva uma função que divida um array (primeiro argumento) em grupos com o comprimento de size (segundo argumento) e os retorne como um array bidimensional.

--hints--

chunkArrayInGroups(["a", "b", "c", "d"], 2) deve retornar [["a", "b"], ["c", "d"]].

assert.deepEqual(chunkArrayInGroups(['a', 'b', 'c', 'd'], 2), [
  ['a', 'b'],
  ['c', 'd']
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5], 3) deve retornar [[0, 1, 2], [3, 4, 5]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5], 3), [
  [0, 1, 2],
  [3, 4, 5]
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5], 2) deve retornar [[0, 1], [2, 3], [4, 5]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5], 2), [
  [0, 1],
  [2, 3],
  [4, 5]
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5], 4) deve retornar [[0, 1, 2, 3], [4, 5]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5], 4), [
  [0, 1, 2, 3],
  [4, 5]
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3) deve retornar [[0, 1, 2], [3, 4, 5], [6]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3), [
  [0, 1, 2],
  [3, 4, 5],
  [6]
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6, 7, 8], 4) deve retornar [[0, 1, 2, 3], [4, 5, 6, 7], [8]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6, 7, 8], 4), [
  [0, 1, 2, 3],
  [4, 5, 6, 7],
  [8]
]);

chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6, 7, 8], 2) deve retornar [[0, 1], [2, 3], [4, 5], [6, 7], [8]].

assert.deepEqual(chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6, 7, 8], 2), [
  [0, 1],
  [2, 3],
  [4, 5],
  [6, 7],
  [8]
]);

--seed--

--seed-contents--

function chunkArrayInGroups(arr, size) {
  return arr;
}

chunkArrayInGroups(["a", "b", "c", "d"], 2);

--solutions--

function chunkArrayInGroups(arr, size) {
  let out = [];

  for (let i = 0; i < arr.length; i += size) {
    out.push(arr.slice(i, i + size));
  }

  return out;
}

chunkArrayInGroups(["a", "b", "c", "d"], 2);

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