430 lines
13 KiB
JavaScript
430 lines
13 KiB
JavaScript
import test from 'tape';
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import moment from 'moment-timezone';
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import sinon from 'sinon';
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import {
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prepUniqueDaysByHours,
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calcCurrentStreak,
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calcLongestStreak
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} from './user-stats';
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// setting now to 2016-02-03T11:00:00 (PST)
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const clock = sinon.useFakeTimers(1454526000000);
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const PST = 'America/Los_Angeles';
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test('Prepare calendar items', function(t) {
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t.plan(5);
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t.deepEqual(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('8/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('8/3/2015 20:00', 'M/D/YYYY H:mm').valueOf()
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]),
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[1438567200000],
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'should return correct epoch when all entries fall into one day in UTC'
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);
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t.deepEqual(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
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]),
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[1438567200000],
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'should return correct epoch when given two identical dates'
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);
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t.deepEqual(
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prepUniqueDaysByHours([
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// 8/2/2015 in America/Los_Angeles
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('8/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('8/3/2015 20:00', 'M/D/YYYY H:mm').valueOf()
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], PST),
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[1438567200000, 1438610400000],
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'should return 2 epochs when dates fall into two days in PST'
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);
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t.deepEqual(
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prepUniqueDaysByHours([
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moment.utc('8/1/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('3/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/30/2014 20:00', 'M/D/YYYY H:mm').valueOf()
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]),
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[1412107200000, 1425391200000, 1438394400000],
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'should return 3 epochs when dates fall into three days'
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);
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t.deepEqual(
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prepUniqueDaysByHours([
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1438387200000, 1425340800000, 1412035200000
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]),
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[1412035200000, 1425340800000, 1438387200000],
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'should return same but sorted array if all input dates are start of day'
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);
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});
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test('Current streak calculation', function(t) {
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t.plan(11);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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1,
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'should return 1 day when today one challenge was completed'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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1,
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'should return 1 day when today more than one challenge was completed'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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0,
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'should return 0 day when today 0 challenges were completed'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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2,
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'should return 2 days when today and yesterday challenges were completed'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc(moment.utc().subtract(2, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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3,
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'should return 3 when today and for two days before user was activity'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(47, 'hours')).valueOf(),
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moment.utc(moment.utc().subtract(11, 'hours')).valueOf()
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])
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),
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1,
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'should return 1 when there is 1.5 days long break and ' +
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'dates fall into two days separated by third'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(40, 'hours')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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2,
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'should return 2 when the break is more than 1.5 days ' +
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'but dates fall into two consecutive days'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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1,
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'should return correct count in default timezone UTC ' +
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'given `undefined` timezone'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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], PST),
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PST
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),
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2,
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'should return 2 days when today and yesterday ' +
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'challenges were completed given PST'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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1453174506164, 1453175436725, 1453252466853, 1453294968225,
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1453383782844, 1453431903117, 1453471373080, 1453594733026,
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1453645014058, 1453746762747, 1453747659197, 1453748029416,
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1453818029213, 1453951796007, 1453988570615, 1454069704441,
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1454203673979, 1454294055498, 1454333545125, 1454415163903,
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1454519128123, moment.tz(PST).valueOf()
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], PST),
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PST
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),
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17,
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'should return 17 when there is no break in given timezone ' +
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'(but would be the break if in UTC)'
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);
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t.equal(
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calcCurrentStreak(
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prepUniqueDaysByHours([
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1453174506164, 1453175436725, 1453252466853, 1453294968225,
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1453383782844, 1453431903117, 1453471373080, 1453594733026,
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1453645014058, 1453746762747, 1453747659197, 1453748029416,
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1453818029213, 1453951796007, 1453988570615, 1454069704441,
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1454203673979, 1454294055498, 1454333545125, 1454415163903,
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1454519128123, moment.utc().valueOf()
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])
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),
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4,
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'should return 4 when there is a break in UTC ' +
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'(but would be no break in PST)'
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);
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});
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test('Longest streak calculation', function(t) {
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t.plan(14);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('9/12/2015 4:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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1,
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'should return 1 when there is the only one one-day-long streak available'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 1:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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4,
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'should return 4 when there is the only one ' +
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'more-than-one-days-long streak available'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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1,
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'should return 1 when there is only one one-day-long streak and it is today'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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2,
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'should return 2 when yesterday and today makes longest streak'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/4/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/5/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/6/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/7/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('11/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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4,
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'should return 4 when there is a month long break'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 15:30', 'M/D/YYYY H:mm').valueOf(),
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moment.utc(moment.utc('9/12/2015 15:30', 'M/D/YYYY H:mm')
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.add(37, 'hours')).valueOf(),
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moment.utc('9/14/2015 22:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/15/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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2,
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'should return 2 when there is a more than 1.5 days ' +
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'long break of (36 hours)'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc(moment.utc().subtract(2, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc().valueOf()
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])
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),
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4,
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'should return 4 when the longest streak consist of ' +
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'several same day timestamps'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('10/14/2015 5:00', 'M/D/YYYY H:mm').valueOf()
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])
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),
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4,
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'should return 4 when there are several longest streaks (same length)'
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);
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let cals = [];
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const n = 100;
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for (var i = 0; i < n; i++) {
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cals.push(moment.utc(moment.utc().subtract(i, 'days')).valueOf());
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}
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t.equal(
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calcLongestStreak(prepUniqueDaysByHours(cals)),
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n,
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'should return correct longest streak when there is a very long period'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
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moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
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])
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),
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2,
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'should return correct longest streak in default timezone ' +
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'UTC given `undefined` timezone'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 1:00', 'M/D/YYYY H:mm').valueOf()
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]), PST
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),
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4,
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'should return 4 when there is the only one more-than-one-days-long ' +
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'streak available given PST'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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moment.utc('9/11/2015 23:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/13/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
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moment.utc('9/14/2015 6:00', 'M/D/YYYY H:mm').valueOf()
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], PST), PST
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),
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3,
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'should return 3 when longest streak is 3 in PST ' +
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'(but would be different in default timezone UTC)'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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1453174506164, 1453175436725, 1453252466853, 1453294968225,
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1453383782844, 1453431903117, 1453471373080, 1453594733026,
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1453645014058, 1453746762747, 1453747659197, 1453748029416,
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1453818029213, 1453951796007, 1453988570615, 1454069704441,
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1454203673979, 1454294055498, 1454333545125, 1454415163903,
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1454519128123, moment.tz(PST).valueOf()
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], PST),
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PST
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),
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17,
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'should return 17 when there is no break in PST ' +
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'(but would be break in UTC) and it is current'
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);
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t.equal(
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calcLongestStreak(
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prepUniqueDaysByHours([
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1453174506164, 1453175436725, 1453252466853, 1453294968225,
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1453383782844, 1453431903117, 1453471373080, 1453594733026,
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1453645014058, 1453746762747, 1453747659197, 1453748029416,
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1453818029213, 1453951796007, 1453988570615, 1454069704441,
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1454203673979, 1454294055498, 1454333545125, 1454415163903,
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1454519128123, moment.utc().valueOf()
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])
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),
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4,
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'should return 4 when there is a break in UTC (but no break in PST)'
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);
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});
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test.onFinish(() => {
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clock.restore();
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});
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