freeCodeCamp/curriculum/challenges/chinese-traditional/02-javascript-algorithms-an.../functional-programming/learn-about-functional-prog...

87 lines
1.9 KiB
Markdown
Raw Normal View History

---
id: 587d7b8d367417b2b2512b5b
title: 學習函數式編程
challengeType: 1
forumTopicId: 301233
dashedName: learn-about-functional-programming
---
# --description--
函數式編程是一種方案簡單、功能獨立、對作用域外沒有任何副作用的編程範式:`INPUT -> PROCESS -> OUTPUT`。
函數式編程:
1功能獨立——不依賴於程序的狀態比如可能發生變化的全局變量
2純函數——同一個輸入永遠能得到同一個輸出
3有限的副作用——可以嚴格地限制函數外部對狀態的更改。
# --instructions--
freeCodeCamp 的成員們愛喝茶。
在代碼編輯器中,已經爲你定義好了`prepareTea`和`getTea`函數。 調用 `getTea` 函數爲團隊準備 40 杯茶,並將它們存儲在 `tea4TeamFCC` 變量裏。
# --hints--
`tea4TeamFCC` 變量裏應有 40 杯爲團隊準備的茶。
```js
assert(tea4TeamFCC.length === 40);
```
`tea4TeamFCC` 變量裏應有幾杯 greenTea綠茶
```js
assert(tea4TeamFCC[0] === 'greenTea');
```
# --seed--
## --seed-contents--
```js
// Function that returns a string representing a cup of green tea
const prepareTea = () => 'greenTea';
/*
Given a function (representing the tea type) and number of cups needed, the
following function returns an array of strings (each representing a cup of
a specific type of tea).
*/
const getTea = (numOfCups) => {
const teaCups = [];
for(let cups = 1; cups <= numOfCups; cups += 1) {
const teaCup = prepareTea();
teaCups.push(teaCup);
}
return teaCups;
};
// Only change code below this line
const tea4TeamFCC = null;
// Only change code above this line
```
# --solutions--
```js
const prepareTea = () => 'greenTea';
const getTea = (numOfCups) => {
const teaCups = [];
for(let cups = 1; cups <= numOfCups; cups += 1) {
const teaCup = prepareTea();
teaCups.push(teaCup);
}
return teaCups;
};
const tea4TeamFCC = getTea(40);
```