freeCodeCamp/curriculum/challenges/chinese-traditional/02-javascript-algorithms-an.../functional-programming/learn-about-functional-prog...

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id title challengeType forumTopicId dashedName
587d7b8d367417b2b2512b5b 學習函數式編程 1 301233 learn-about-functional-programming

--description--

函數式編程是一種方案簡單、功能獨立、對作用域外沒有任何副作用的編程範式:INPUT -> PROCESS -> OUTPUT

函數式編程:

1功能獨立——不依賴於程序的狀態比如可能發生變化的全局變量

2純函數——同一個輸入永遠能得到同一個輸出

3有限的副作用——可以嚴格地限制函數外部對狀態的更改。

--instructions--

freeCodeCamp 的成員們愛喝茶。

在代碼編輯器中,已經爲你定義好了prepareTeagetTea函數。 調用 getTea 函數爲團隊準備 40 杯茶,並將它們存儲在 tea4TeamFCC 變量裏。

--hints--

tea4TeamFCC 變量裏應有 40 杯爲團隊準備的茶。

assert(tea4TeamFCC.length === 40);

tea4TeamFCC 變量裏應有幾杯 greenTea綠茶

assert(tea4TeamFCC[0] === 'greenTea');

--seed--

--seed-contents--

// Function that returns a string representing a cup of green tea
const prepareTea = () => 'greenTea';

/*
Given a function (representing the tea type) and number of cups needed, the
following function returns an array of strings (each representing a cup of
a specific type of tea).
*/
const getTea = (numOfCups) => {
  const teaCups = [];

  for(let cups = 1; cups <= numOfCups; cups += 1) {
    const teaCup = prepareTea();
    teaCups.push(teaCup);
  }
  return teaCups;
};

// Only change code below this line
const tea4TeamFCC = null;
// Only change code above this line

--solutions--

const prepareTea = () => 'greenTea';

const getTea = (numOfCups) => {
  const teaCups = [];

  for(let cups = 1; cups <= numOfCups; cups += 1) {
    const teaCup = prepareTea();
    teaCups.push(teaCup);
  }

  return teaCups;
};

const tea4TeamFCC = getTea(40);