749 B
749 B
id | title | challengeType | forumTopicId |
---|---|---|---|
5900f4291000cf542c50ff3b | Problem 188: The hyperexponentiation of a number | 5 | 301824 |
--description--
The hyperexponentiation or tetration of a number a by a positive integer b, denoted by a↑↑b or ba, is recursively defined by:
a↑↑1 = a,
a↑↑(k+1) = a(a↑↑k).
Thus we have e.g. 3↑↑2 = 33 = 27, hence 3↑↑3 = 327 = 7625597484987 and 3↑↑4 is roughly 103.6383346400240996*10^12. Find the last 8 digits of 1777↑↑1855.
--hints--
euler188()
should return 95962097.
assert.strictEqual(euler188(), 95962097);
--seed--
--seed-contents--
function euler188() {
return true;
}
euler188();
--solutions--
// solution required