898 B
898 B
title |
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Multiples of 3 and 5 |
Problem 1: Multiples of 3 and 5
Method:
- We can find if a number is divisble by another number with the help of
%
modulo operator. num1 % num2
returns0
if there's no remainder while doingnum1/num2
.- Starting from
i = 3
because that's the first number that's divisble by 3 or 5, we loop through till thenumber
provided. - If the number is divisible either by 3 or 5, we add that to the variable
sum
and finally return it.
Solution:
function multiplesOf3and5(number) {
let sum = 0, i = 3;
while (i < number){
if (i % 3 == 0 || i % 5 == 0) sum += i;
i++;
}
return sum;
}