freeCodeCamp/curriculum/challenges/italian/10-coding-interview-prep/data-structures/perform-a-subset-check-on-t...

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---
id: 587d8254367417b2b2512c6f
title: Eseguire un controllo di sottoinsieme su due insiemi di dati
challengeType: 1
forumTopicId: 301707
dashedName: perform-a-subset-check-on-two-sets-of-data
---
# --description--
In questo esercizio, eseguiremo un test subset su 2 set di dati. Creeremo un metodo sulla nostra struttura di dati `Set` chiamato `isSubsetOf`. Questo confronterà il primo set con il secondo, e se il primo set è pienamente contenuto nel secondo, restituirà `true`.
Per esempio, se `setA = ['a','b']` e `setB = ['a','b','c','d']`, allora `setA` è un subset di `setB`, quindi `setA.isSubsetOf(setB)` dovrebbe restituire `true`.
# --hints--
La tua classe `Set` dovrebbe avere un metodo `isSubsetOf`.
```js
assert(
(function () {
var test = new Set();
return typeof test.isSubsetOf === 'function';
})()
);
```
Il primo `Set` dovrebbe essere contenuto nel secondo `Set`.
```js
assert(
(function () {
var setA = new Set();
var setB = new Set();
setA.add('a');
setB.add('b');
setB.add('c');
setB.add('a');
setB.add('d');
var aIsSubsetOfB = setA.isSubsetOf(setB);
return aIsSubsetOfB === true;
})()
);
```
`['a', 'b'].isSubsetOf(['a', 'b', 'c', 'd'])` dovrebbe restituire `true`.
```js
assert(
(function () {
var setA = new Set();
var setB = new Set();
setA.add('a');
setA.add('b');
setB.add('a');
setB.add('b');
setB.add('c');
setB.add('d');
var aIsSubsetOfB = setA.isSubsetOf(setB);
return aIsSubsetOfB === true;
})()
);
```
`['a', 'b', 'c'].isSubsetOf(['a', 'b'])` dovrebbe restituire `false`.
```js
assert(
(function () {
var setA = new Set();
var setB = new Set();
setA.add('a');
setA.add('b');
setA.add('c');
setB.add('a');
setB.add('b');
var aIsSubsetOfB = setA.isSubsetOf(setB);
return aIsSubsetOfB === false;
})()
);
```
`[].isSubsetOf([])` dovrebbe restituire `true`.
```js
assert(
(function () {
var setA = new Set();
var setB = new Set();
var aIsSubsetOfB = setA.isSubsetOf(setB);
return aIsSubsetOfB === true;
})()
);
```
`['a', 'b'].isSubsetOf(['c', 'd'])` dovrebbe restituire `false`.
```js
assert(
(function () {
var setA = new Set();
var setB = new Set();
setA.add('a');
setA.add('b');
setB.add('c');
setB.add('d');
var aIsSubsetOfB = setA.isSubsetOf(setB);
return aIsSubsetOfB === false;
})()
);
```
# --seed--
## --seed-contents--
```js
class Set {
constructor() {
// This will hold the set
this.dictionary = {};
this.length = 0;
}
// This method will check for the presence of an element and return true or false
has(element) {
return this.dictionary[element] !== undefined;
}
// This method will return all the values in the set
values() {
return Object.keys(this.dictionary);
}
// This method will add an element to the set
add(element) {
if (!this.has(element)) {
this.dictionary[element] = true;
this.length++;
return true;
}
return false;
}
// This method will remove an element from a set
remove(element) {
if (this.has(element)) {
delete this.dictionary[element];
this.length--;
return true;
}
return false;
}
// This method will return the size of the set
size() {
return this.length;
}
// This is our union method
union(set) {
const newSet = new Set();
this.values().forEach(value => {
newSet.add(value);
})
set.values().forEach(value => {
newSet.add(value);
})
return newSet;
}
// This is our intersection method
intersection(set) {
const newSet = new Set();
let largeSet;
let smallSet;
if (this.dictionary.length > set.length) {
largeSet = this;
smallSet = set;
} else {
largeSet = set;
smallSet = this;
}
smallSet.values().forEach(value => {
if (largeSet.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
difference(set) {
const newSet = new Set();
this.values().forEach(value => {
if (!set.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
// Only change code below this line
// Only change code above this line
}
```
# --solutions--
```js
class Set {
constructor() {
this.dictionary = {};
this.length = 0;
}
has(element) {
return this.dictionary[element] !== undefined;
}
values() {
return Object.keys(this.dictionary);
}
add(element) {
if (!this.has(element)) {
this.dictionary[element] = true;
this.length++;
return true;
}
return false;
}
remove(element) {
if (this.has(element)) {
delete this.dictionary[element];
this.length--;
return true;
}
return false;
}
size() {
return this.length;
}
union(set) {
const newSet = new Set();
this.values().forEach(value => {
newSet.add(value);
})
set.values().forEach(value => {
newSet.add(value);
})
return newSet;
}
intersection(set) {
const newSet = new Set();
let largeSet;
let smallSet;
if (this.dictionary.length > set.length) {
largeSet = this;
smallSet = set;
} else {
largeSet = set;
smallSet = this;
}
smallSet.values().forEach(value => {
if (largeSet.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
difference(set) {
const newSet = new Set();
this.values().forEach(value => {
if (!set.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
isSubsetOf(set) {
for(const value of this.values()){
if(!set.dictionary[value]) return false;
}
return true
}
}
```