freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-an.../es6/use-destructuring-assignmen...

2.0 KiB

id title challengeType forumTopicId dashedName
587d7b89367417b2b2512b4a 使用解构赋值从嵌套对象中分配变量 1 301214 use-destructuring-assignment-to-assign-variables-from-nested-objects

--description--

同样,我们可以将 嵌套的对象解构到变量中。

请看以下代码:

const user = {
  johnDoe: { 
    age: 34,
    email: 'johnDoe@freeCodeCamp.com'
  }
};

这是解构对象的属性并赋值给相同名字的变量:

const { johnDoe: { age, email }} = user;

这是将对象的属性值指定给一个不同的名字:

const { johnDoe: { age: userAge, email: userEmail }} = user;

--instructions--

将两个赋值语句替换成等价的解构赋值。lowTodayhighToday 应该为 LOCAL_FORECASTtoday.lowtoday.high 的值。

--hints--

不能使用 ES5 的赋值语句。

assert(
  !code.match(/lowToday = LOCAL_FORECAST\.today\.low/g) &&
    !code.match(/highToday = LOCAL_FORECAST\.today.high/g)
);

应该使用解构创建 lowToday 变量。

assert(
  code.match(
    /(var|const|let)\s*{\s*today\s*:\s*{\s*(low\s*:\s*lowToday[^}]*|[^,]*,\s*low\s*:\s*lowToday\s*)}\s*}\s*=\s*LOCAL_FORECAST(;|\s+|\/\/)/g
  )
);

应该使用解构创建 highToday 变量。

assert(
  code.match(
    /(var|const|let)\s*{\s*today\s*:\s*{\s*(high\s*:\s*highToday[^}]*|[^,]*,\s*high\s*:\s*highToday\s*)}\s*}\s*=\s*LOCAL_FORECAST(;|\s+|\/\/)/g
  )
);

--seed--

--seed-contents--

const LOCAL_FORECAST = {
  yesterday: { low: 61, high: 75 },
  today: { low: 64, high: 77 },
  tomorrow: { low: 68, high: 80 }
};

// Only change code below this line
  
const lowToday = LOCAL_FORECAST.today.low;
const highToday = LOCAL_FORECAST.today.high;

// Only change code above this line

--solutions--

const LOCAL_FORECAST = {
  yesterday: { low: 61, high: 75 },
  today: { low: 64, high: 77 },
  tomorrow: { low: 68, high: 80 }
};
 
const { today: { low: lowToday, high: highToday }} = LOCAL_FORECAST;