freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-20-factorial-digit-...

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---
id: 5900f3801000cf542c50fe93
title: 问题20因子数字和
challengeType: 5
videoUrl: ''
dashedName: problem-20-factorial-digit-sum
---
# --description--
`n` !意味着`n` × `n` - 1×...×3×2×1例如10 = 10×9×...×3×2×1 = 3628800
和数字10中的数字之和是3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.找到数字之和`n`
# --hints--
`sumFactorialDigits(10)`应该返回27。
```js
assert.strictEqual(sumFactorialDigits(10), 27);
```
`sumFactorialDigits(25)`应该返回72。
```js
assert.strictEqual(sumFactorialDigits(25), 72);
```
`sumFactorialDigits(50)`应该返回216。
```js
assert.strictEqual(sumFactorialDigits(50), 216);
```
`sumFactorialDigits(75)`应该返回432。
```js
assert.strictEqual(sumFactorialDigits(75), 432);
```
`sumFactorialDigits(100)`应该返回648。
```js
assert.strictEqual(sumFactorialDigits(100), 648);
```
# --seed--
## --seed-contents--
```js
function sumFactorialDigits(n) {
return n;
}
sumFactorialDigits(100);
```
# --solutions--
```js
let factorial = (n) => n <= 1 ? BigInt(n) : BigInt(n) * BigInt(factorial(--n));
let sumDigits = n => n.toString().split('').map(x => parseInt(x)).reduce((a,b) => a + b);
function sumFactorialDigits(n) {
return sumDigits(factorial(n));
}
```