freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-358-cyclic-numbers.md

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---
id: 5900f4d21000cf542c50ffe5
title: 问题358循环数
challengeType: 5
videoUrl: ''
dashedName: problem-358-cyclic-numbers
---
# --description--
具有n位数字的循环数具有一个非常有趣的属性
当乘以1、2、3、4... n时所有乘积都具有完全相同的数字并且顺序相同但是以循环方式旋转
最小的循环数是6位数字142857 142857×1 = 142857 142857×2 = 285714 142857×3 = 428571 142857×4 = 571428 142857×5 = 714285 142857×6 = 857142
下一个循环号是16位数字0588235294117647 0588235294117647×1 = 0588235294117647 0588235294117647×2 = 1176470588235294 0588235294117647×3 = 1764705882352941 ... 0588235294117647×16 = 9411764705882352
请注意,对于循环数,前导零很重要。
只有一个循环数其最左边的11个数字为00000000137最右边的5个数字为56789即其形式为00000000137 ... 56789中间是未知数字。 查找所有数字的总和。
# --hints--
`euler358()`应返回3284144505。
```js
assert.strictEqual(euler358(), 3284144505);
```
# --seed--
## --seed-contents--
```js
function euler358() {
return true;
}
euler358();
```
# --solutions--
```js
// solution required
```