freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-448-average-least-c...

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---
id: 5900f52c1000cf542c51003f
title: 问题448平均最小公倍数
challengeType: 5
videoUrl: ''
dashedName: problem-448-average-least-common-multiple
---
# --description--
函数lcmab表示a和b的最小公倍数。设An为1≤i≤n的lcmni的平均值。例如A2=2 + 2/ 2 = 2且A10=10 + 10 + 30 + 20 + 10 + 30 + 70 + 40 + 90 + 10/ 10 = 32。
令Sn=ΣAk为1≤k≤n。 S100= 122726。
找到S99999999019mod 999999017。
# --hints--
`euler448()`应该返回106467648。
```js
assert.strictEqual(euler448(), 106467648);
```
# --seed--
## --seed-contents--
```js
function euler448() {
return true;
}
euler448();
```
# --solutions--
```js
// solution required
```