freeCodeCamp/guide/english/certifications/javascript-algorithms-and-data-structures/es6/use-destructuring-assignment-to-pass-an-object-as-a-functions-parameters/index.md

title
Use Destructuring Assignment to Pass an Object as a Function's Parameters

Use Destructuring Assignment to Pass an Object as a Function's Parameters

You could pass the entire object, and then pick the specific attributes you want by using the . operator. But ES6 offers a more elegant option!

Hint 1:

Get rid of the stats, and see if you can destructure it. We need the max and min of stats.

Spoiler Warning - Solutions Ahead!

Solution 1:

const half = (function() {
  "use strict"; // do not change this line

  // change code below this line
  return function half({max, min}) {
    // use function argument destructuring
    return (max + min) / 2.0;
  };
  // change code above this line

})();

Notice that we are destructuring stats to pass two of its attributes - max and min - to the function. Don't forget to the modify the second return statement. Change stats.max to just max, and change stats.min to just min.

Solution 2:

Here is another solution that works. Not much of a difference, other than the fact that the function doesn't have a name.

const half = (function() {
  "use strict"; // do not change this line

  // change code below this line
  return (({max, min}) => {
    // use function argument destructuring
    return (max + min) / 2.0;
  });
  // change code above this line

})();