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id	title	challengeType	videoUrl	forumTopicId	dashedName
56533eb9ac21ba0edf2244df	在 Switch 語句添加多個相同選項	1	https://scrimba.com/c/cdBKWCV	18242	multiple-identical-options-in-switch-statements

--description--

如果你忘了給 switch 的每一條 case 添加 break，那麼後續的 case 會一直執行，直到遇見 break 爲止。如果你想爲 switch 中的多個不同的輸入設置相同的結果，可以這樣寫：

var result = "";
switch(val) {
  case 1:
  case 2:
  case 3:
    result = "1, 2, or 3";
    break;
  case 4:
    result = "4 alone";
}

這樣，1、2、3 都會有相同的結果。

--instructions--

請寫一個 switch 語句，按如下條件設置 answer ：
1-3 - Low
4-6 - Mid
7-9 - High

提示： 你的 case 應寫全範圍中的每一個數字。

--hints--

sequentialSizes(1) 應該返回字符串 Low

assert(sequentialSizes(1) === 'Low');

sequentialSizes(2) 應該返回字符串 Low

assert(sequentialSizes(2) === 'Low');

sequentialSizes(3) 應該返回字符串 Low

assert(sequentialSizes(3) === 'Low');

sequentialSizes(4) 應該返回字符串 Mid

assert(sequentialSizes(4) === 'Mid');

sequentialSizes(5) 應該返回字符串 Mid

assert(sequentialSizes(5) === 'Mid');

sequentialSizes(6) 應該返回字符串 Mid

assert(sequentialSizes(6) === 'Mid');

sequentialSizes(7) 應該返回字符串 High

assert(sequentialSizes(7) === 'High');

sequentialSizes(8) 應該返回字符串 High

assert(sequentialSizes(8) === 'High');

sequentialSizes(9) 應該返回字符串 High

assert(sequentialSizes(9) === 'High');

你不應使用 if 或 else 語句。

assert(!/else/g.test(code) || !/if/g.test(code));

你應該編寫 9 個case語句。

assert(code.match(/case/g).length === 9);

--seed--

--seed-contents--

function sequentialSizes(val) {
  var answer = "";
  // Only change code below this line



  // Only change code above this line
  return answer;
}

sequentialSizes(1);

--solutions--

function sequentialSizes(val) {
  var answer = "";

  switch(val) {
    case 1:
    case 2:
    case 3:
      answer = "Low";
      break;
    case 4:
    case 5:
    case 6:
      answer = "Mid";
      break;
    case 7:
    case 8:
    case 9:
      answer = "High";
  }

  return answer;
}

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