freeCodeCamp/guide/chinese/mathematics/converting-from-decimal-to-.../index.md

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---
title: Converting from Decimal to Binary
localeTitle: 从十进制转换为二进制
---
## 从十进制转换为二进制
您可以使用余数将十进制数转换为二进制数。
### 一般方法
1将原始十进制数除以2并记录商和余数。 2重复第一步用你找到的最后一个商替换原始十进制数直到得到一个等于0的商。 3将你记录的最后一个余数作为你的MSB最高位和你记录的第一个余数作为你的LSB最低有效位。记下与生成它们的顺序相反的余数。
### 例子
将十进制数30转换为二进制数。
```
30 / 2 = 15 r 0
15 / 2 = 7 r 1
7 / 2 = 3 r 1
3 / 2 = 1 r 1
1 / 2 = 0 r 1
Writing out the remainders bottom to top gives you the bit pattern:
11110
Checking your answer by converting the binary number back to decimal:
(1*2^4)+(1*2^3)+(1*2^2)+(1*2^1)+(0*2^0) = 30
So your answer is correct.
```
将十进制数116转换为二进制数。
```
116 / 2 = 58 r 0
58 / 2 = 29 r 0
29 / 2 = 14 r 1
14 / 2 = 7 r 0
7 / 2 = 3 r 1
3 / 2 = 1 r 1
1 / 2 = 0 r 1
Writing out the remainders bottom to top gives you the bit pattern:
1110100
Checking your answer by converting the binary number back to decimal:
(1*2^6)+(1*2^5)+(1*2^4)+(0*2^3)+(1*2^2)+(0*2^1)+(0*2^0) = 116
So your answer is correct.
```