56 lines
1.1 KiB
Markdown
56 lines
1.1 KiB
Markdown
---
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id: 5900f52c1000cf542c51003f
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challengeType: 5
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title: 'Problem 448: Average least common multiple'
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videoUrl: ''
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localeTitle: 问题448:平均最小公倍数
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---
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## Description
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<section id="description">函数lcm(a,b)表示a和b的最小公倍数。设A(n)为1≤i≤n的lcm(n,i)的平均值。例如:A(2)=(2 + 2)/ 2 = 2且A(10)=(10 + 10 + 30 + 20 + 10 + 30 + 70 + 40 + 90 + 10)/ 10 = 32。 <p>令S(n)=ΣA(k)为1≤k≤n。 S(100)= 122726。 </p><p>找到S(99999999019)mod 999999017。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>euler448()</code>应该返回106467648。
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testString: 'assert.strictEqual(euler448(), 106467648, "<code>euler448()</code> should return 106467648.");'
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function euler448() {
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// Good luck!
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return true;
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}
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euler448();
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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</section>
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