45 lines
815 B
Markdown
45 lines
815 B
Markdown
---
|
|
id: 5900f3e41000cf542c50fef6
|
|
title: 'Problem 119: Digit power sum'
|
|
challengeType: 5
|
|
forumTopicId: 301745
|
|
dashedName: problem-119-digit-power-sum
|
|
---
|
|
|
|
# --description--
|
|
|
|
The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
|
|
|
|
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
|
|
|
|
You are given that a2 = 512 and a10 = 614656.
|
|
|
|
Find a30.
|
|
|
|
# --hints--
|
|
|
|
`euler119()` should return 248155780267521.
|
|
|
|
```js
|
|
assert.strictEqual(euler119(), 248155780267521);
|
|
```
|
|
|
|
# --seed--
|
|
|
|
## --seed-contents--
|
|
|
|
```js
|
|
function euler119() {
|
|
|
|
return true;
|
|
}
|
|
|
|
euler119();
|
|
```
|
|
|
|
# --solutions--
|
|
|
|
```js
|
|
// solution required
|
|
```
|