freeCodeCamp/curriculum/challenges/english/02-javascript-algorithms-an.../functional-programming-spre.../part-007.md

1.6 KiB

id title challengeType isHidden
5d7925337954ed57a565a135 Part 007 0 true

Description

This is possible because the anonymous function has been immediately assigned to a value - this is effectively the same as using a named function.

Rewrite addVar using ES6's arrow syntax:

const fn = (x, y) => x;

Note that the value is returned implicitly.

Instructions

Tests

tests:
  - text: See description above for instructions.
    testString: assert(code.replace(/\s/g, "").includes("constaddVar=(x,y)=>x+y"));

Challenge Seed

<script>

const addVar = function(x, y) {
  return x + y;
};

const infixToFunction = {};


</script>

Before Test

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>Spreadsheet</title>
  <style>
    #container {
      display: grid;
      grid-template-columns: 50px repeat(10, 200px);
      grid-template-rows: repeat(11, 30px);
    }
    .label {
      background-color: lightgray;
      text-align: center;
      vertical-align: middle;
      line-height: 30px;
    }
  </style>
</head>
<body>
<div id="container">
  <div></div>
</div>

After Test

</body>
</html>

Solution

<script>
const addVar = (x, y) => x + y;

const infixToFunction = {};
</script>