freeCodeCamp/curriculum/challenges/english/05-apis-and-microservices/mongodb-and-mongoose/create-many-records-with-mo...

1.9 KiB

id title challengeType forumTopicId dashedName
587d7fb7367417b2b2512c0a Create Many Records with model.create() 2 301537 create-many-records-with-model-create

--description--

Sometimes you need to create many instances of your models, e.g. when seeding a database with initial data. Model.create() takes an array of objects like [{name: 'John', ...}, {...}, ...] as the first argument, and saves them all in the db.

--instructions--

Modify the createManyPeople function to create many people using Model.create() with the argument arrayOfPeople.

Note: You can reuse the model you instantiated in the previous exercise.

--hints--

Creating many db items at once should succeed

(getUserInput) =>
  $.ajax({
    url: getUserInput('url') + '/_api/create-many-people',
    type: 'POST',
    contentType: 'application/json',
    data: JSON.stringify([
      { name: 'John', age: 24, favoriteFoods: ['pizza', 'salad'] },
      { name: 'Mary', age: 21, favoriteFoods: ['onions', 'chicken'] }
    ])
  }).then(
    (data) => {
      assert.isArray(data, 'the response should be an array');
      assert.equal(
        data.length,
        2,
        'the response does not contain the expected number of items'
      );
      assert.equal(data[0].name, 'John', 'The first item is not correct');
      assert.equal(
        data[0].__v,
        0,
        'The first item should be not previously edited'
      );
      assert.equal(data[1].name, 'Mary', 'The second item is not correct');
      assert.equal(
        data[1].__v,
        0,
        'The second item should be not previously edited'
      );
    },
    (xhr) => {
      throw new Error(xhr.responseText);
    }
  );

--solutions--

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