freeCodeCamp/curriculum/challenges/espanol/10-coding-interview-prep/rosetta-code/top-rank-per-group.md

6.1 KiB

id title challengeType forumTopicId dashedName
595011cba5a81735713873bd Top rank per group 5 302339 top-rank-per-group

--description--

Find the top n ranked data in each group, where n is provided as a parameter. Name of the rank and the group are also provided as parameter.

Given the following data:

testData1 = [
  { name: 'Tyler Bennett', id: 'E10297', salary: 32000, dept: 'D101' },
  { name: 'John Rappl', id: 'E21437', salary: 47000, dept: 'D050' },
  { name: 'George Woltman', id: 'E00127', salary: 53500, dept: 'D101' },
  { name: 'Adam Smith', id: 'E63535', salary: 18000, dept: 'D202' },
  { name: 'Claire Buckman', id: 'E39876', salary: 27800, dept: 'D202' },
  { name: 'David McClellan', id: 'E04242', salary: 41500, dept: 'D101' },
  { name: 'Rich Holcomb', id: 'E01234', salary: 49500, dept: 'D202' },
  { name: 'Nathan Adams', id: 'E41298', salary: 21900, dept: 'D050' },
  { name: 'Richard Potter', id: 'E43128', salary: 15900, dept: 'D101' },
  { name: 'David Motsinger', id: 'E27002', salary: 19250, dept: 'D202' },
  { name: 'Tim Sampair', id: 'E03033', salary: 27000, dept: 'D101' },
  { name: 'Kim Arlich', id: 'E10001', salary: 57000, dept: 'D190' },
  { name: 'Timothy Grove', id: 'E16398', salary: 29900, dept: 'D190' }
];

One could rank top 10 employees in each department by calling:

topRankPerGroup(10, testData1, 'dept', 'salary')

Given the following data:

testData2 = [
  { name: 'Friday 13th', genre: 'horror', rating: 9.9 },
  { name: "Nightmare on Elm's Street", genre: 'horror', rating: 5.7 },
  { name: 'Titanic', genre: 'drama', rating: 7.3 },
  { name: 'Maze Runner', genre: 'scifi', rating: 7.1 },
  { name: 'Blade runner', genre: 'scifi', rating: 8.9 }
];

One could rank the top-rated movie in each genre by calling:

topRankPerGroup(1, testData2, 'genre', 'rating')

The function should return an array with an array for each group containing the top n objects.

For example, given data:

[
  { name: 'Claire Buckman', id: 'E39876', salary: 27800, dept: 'D101' },
  { name: 'Rich Holcomb', id: 'E01234', salary: 49500, dept: 'D050' },
  { name: 'David Motsinger', id: 'E27002', salary: 19250, dept: 'D050' },
  { name: 'Tim Sampair', id: 'E03033', salary: 27000, dept: 'D101' },
  { name: 'Kim Arlich', id: 'E10001', salary: 57000, dept: 'D050' },
  { name: 'Timothy Grove', id: 'E16398', salary: 29900, dept: 'D101' }
];

Top two ranking employees in each department by salary would be:

[ [ { name: 'Kim Arlich', id: 'E10001', salary: 57000, dept: 'D050' },
    { name: 'Rich Holcomb', id: 'E01234', salary: 49500, dept: 'D050' } ],
  [ { name: 'Timothy Grove', id: 'E16398', salary: 29900, dept: 'D101' },
    { name: 'Claire Buckman', id: 'E39876', salary: 27800, dept: 'D101' } ] ]

--hints--

topRankPerGroup should be a function.

assert(typeof topRankPerGroup === 'function');

topRankPerGroup should return undefined on negative n values.

assert(typeof topRankPerGroup(-1, []) === 'undefined');

For topRankPerGroup(10, testData1, 'dept', 'salary'), the first result in the first group should be { name: 'John Rappl', id: 'E21437', salary: 47000, dept: 'D050'}.

assert.deepEqual(res1[0][0], { name: 'John Rappl', id: 'E21437', salary: 47000, dept: 'D050'});

For topRankPerGroup(10, testData1, 'dept', 'salary'), the last result in the last group should be { name: 'Adam Smith', id: 'E63535', salary: 18000, dept: 'D202' }.

assert.deepEqual(res1[3][3], { name: 'Adam Smith', id: 'E63535', salary: 18000, dept: 'D202' });

topRankPerGroup(1, ...) should return only top ranking result per group.

assert.equal(res2[2].length, 1);

topRankPerGroup(2, ...) should return two ranking results per group.

assert.equal(res3[2][1].name, 'Maze Runner');

--seed--

--after-user-code--

const testData1 = [
  { name: 'Tyler Bennett', id: 'E10297', salary: 32000, dept: 'D101' },
  { name: 'John Rappl', id: 'E21437', salary: 47000, dept: 'D050' },
  { name: 'George Woltman', id: 'E00127', salary: 53500, dept: 'D101' },
  { name: 'Adam Smith', id: 'E63535', salary: 18000, dept: 'D202' },
  { name: 'Claire Buckman', id: 'E39876', salary: 27800, dept: 'D202' },
  { name: 'David McClellan', id: 'E04242', salary: 41500, dept: 'D101' },
  { name: 'Rich Holcomb', id: 'E01234', salary: 49500, dept: 'D202' },
  { name: 'Nathan Adams', id: 'E41298', salary: 21900, dept: 'D050' },
  { name: 'Richard Potter', id: 'E43128', salary: 15900, dept: 'D101' },
  { name: 'David Motsinger', id: 'E27002', salary: 19250, dept: 'D202' },
  { name: 'Tim Sampair', id: 'E03033', salary: 27000, dept: 'D101' },
  { name: 'Kim Arlich', id: 'E10001', salary: 57000, dept: 'D190' },
  { name: 'Timothy Grove', id: 'E16398', salary: 29900, dept: 'D190' }
];

const res1 = topRankPerGroup(10, testData1, 'dept', 'salary');

const testData2 = [
  { name: 'Friday 13th', genre: 'horror', rating: 9.9 },
  { name: "Nightmare on Elm's Street", genre: 'horror', rating: 5.7 },
  { name: 'Titanic', genre: 'drama', rating: 7.3 },
  { name: 'Maze Runner', genre: 'scifi', rating: 7.1 },
  { name: 'Blade runner', genre: 'scifi', rating: 8.9 }
];

const res2 = topRankPerGroup(1, testData2, 'genre', 'rating');
const res3 = topRankPerGroup(2, testData2, 'genre', 'rating');

--seed-contents--

function topRankPerGroup(n, data, groupName, rankName) {

  return true;
}

--solutions--

const collectDept = function (arrOfObj, groupName) {
  const collect = arrOfObj.reduce((rtnObj, obj) => {
    if (rtnObj[obj[groupName]] === undefined) {
      rtnObj[obj[groupName]] = [];
    }
    rtnObj[obj[groupName]].push(obj);
    return rtnObj;
  }, {} // initial value to reduce
  );

  return Object.keys(collect).sort().map(key => collect[key]);
};

const sortRank = function (arrOfRankArrs, rankName) {
  return arrOfRankArrs.map(item => item.sort((a, b) => {
    if (a[rankName] > b[rankName]) { return -1; }
    if (a[rankName] < b[rankName]) { return 1; }
    return 0;
  }));
};

function topRankPerGroup(n, data, groupName, rankName) {
  if (n < 0) { return; }
  return sortRank(collectDept(data, groupName),
    rankName).map(list => list.slice(0, n));
}