3.1 KiB
3.1 KiB
title | id | challengeType | isHidden | forumTopicId |
---|---|---|---|---|
Equilibrium index | 5987fd532b954e0f21b5d3f6 | 5 | false | 302255 |
Description
- $A_0 = -7$
- $A_1 = 1$
- $A_2 = 5$
- $A_3 = 2$
- $A_4 = -4$
- $A_5 = 3$
- $A_6 = 0$
3
is an equilibrium index, because:
- $A_0 + A_1 + A_2 = A_4 + A_5 + A_6$
6
is also an equilibrium index, because:
- $A_0 + A_1 + A_2 + A_3 + A_4 + A_5 = 0$
7
is not an equilibrium index, because it is not a valid index of sequence $A$.
Instructions
Tests
tests:
- text: <code>equilibrium</code> should be a function.
testString: assert(typeof equilibrium === 'function');
- text: <code>equilibrium([-7, 1, 5, 2, -4, 3, 0])</code> should return <code>[3,6]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[0]), ans[0]);
- text: <code>equilibrium([2, 4, 6])</code> should return <code>[]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[1]), ans[1]);
- text: <code>equilibrium([2, 9, 2])</code> should return <code>[1]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[2]), ans[2]);
- text: <code>equilibrium([1, -1, 1, -1, 1, -1, 1])</code> should return <code>[0,1,2,3,4,5,6]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[3]), ans[3]);
- text: <code>equilibrium([1])</code> should return <code>[0]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[4]), ans[4]);
- text: <code>equilibrium([])</code> should return <code>[]</code>.
testString: assert.deepEqual(equilibrium(equilibriumTests[5]), ans[5]);
Challenge Seed
function equilibrium(a) {
// Good luck!
}
After Test
const equilibriumTests =
[[-7, 1, 5, 2, -4, 3, 0], // 3, 6
[2, 4, 6], // empty
[2, 9, 2], // 1
[1, -1, 1, -1, 1, -1, 1], // 0,1,2,3,4,5,6
[1], // 0
[] // empty
];
const ans = [[3, 6], [], [1], [0, 1, 2, 3, 4, 5, 6], [0], []];
Solution
function equilibrium(a) {
let N = a.length,
i,
l = [],
r = [],
e = [];
for (l[0] = a[0], r[N - 1] = a[N - 1], i = 1; i < N; i++)
{ l[i] = l[i - 1] + a[i], r[N - i - 1] = r[N - i] + a[N - i - 1]; }
for (i = 0; i < N; i++)
{ if (l[i] === r[i]) e.push(i); }
return e;
}