freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/rosetta-code/gamma-function.english.md

2.4 KiB

title id challengeType isHidden forumTopicId
Gamma function 5a23c84252665b21eecc7e76 5 false 302271

Description

Implement one algorithm (or more) to compute the Gamma ($\Gamma$) function (in the real field only). The Gamma function can be defined as:
$\Gamma(x) = \displaystyle\int_0^\infty t^{x-1}e^{-t} dt$

Instructions

Tests

tests:
  - text: <code>gamma</code> should be a function.
    testString: assert(typeof gamma=='function')
  - text: <code>gamma(.1)</code> should return a number.
    testString: assert(typeof gamma(.1)=='number')
  - text: <code>gamma(.1)</code> should return <code>9.513507698668736</code>.
    testString: assert.equal(round(gamma(.1)), round(9.513507698668736))
  - text: <code>gamma(.2)</code> should return <code>4.590843711998803</code>.
    testString: assert.equal(round(gamma(.2)), round(4.590843711998803))
  - text: <code>gamma(.3)</code> should return <code>2.9915689876875904</code>.
    testString: assert.equal(round(gamma(.3)), round(2.9915689876875904))
  - text: <code>gamma(.4)</code> should return <code>2.218159543757687</code>.
    testString: assert.equal(round(gamma(.4)), round(2.218159543757687))
  - text: <code>gamma(.5)</code> should return <code>1.7724538509055159</code>.
    testString: assert.equal(round(gamma(.5)), round(1.7724538509055159))

Challenge Seed

function gamma(x) {
  // Good luck!
}

After Test

function round(x) {
  return Number(x).toPrecision(13);
}

Solution

function gamma(x) {
  var p = [0.99999999999980993, 676.5203681218851, -1259.1392167224028,
  771.32342877765313, -176.61502916214059, 12.507343278686905,
  -0.13857109526572012, 9.9843695780195716e-6, 1.5056327351493116e-7
  ];

  var g = 7;
  if (x < 0.5) {
    return Math.PI / (Math.sin(Math.PI * x) * gamma(1 - x));
  }

  x -= 1;
  var a = p[0];
  var t = x + g + 0.5;
  for (var i = 1; i < p.length; i++) {
  a += p[i] / (x + i);
  }

  var result=Math.sqrt(2 * Math.PI) * Math.pow(t, x + 0.5) * Math.exp(-t) * a;

  return result;
}