1.7 KiB
1.7 KiB
id | challengeType | title |
---|---|---|
5900f3801000cf542c50fe93 | 5 | Problem 20: Factorial digit sum |
Description
and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27. Find the sum of the digits n!
Instructions
Tests
tests:
- text: <code>sumFactorialDigits(10)</code> should return 27.
testString: assert.strictEqual(sumFactorialDigits(10), 27, '<code>sumFactorialDigits(10)</code> should return 27.');
- text: <code>sumFactorialDigits(25)</code> should return 72.
testString: assert.strictEqual(sumFactorialDigits(25), 72, '<code>sumFactorialDigits(25)</code> should return 72.');
- text: <code>sumFactorialDigits(50)</code> should return 216.
testString: assert.strictEqual(sumFactorialDigits(50), 216, '<code>sumFactorialDigits(50)</code> should return 216.');
- text: <code>sumFactorialDigits(75)</code> should return 432.
testString: assert.strictEqual(sumFactorialDigits(75), 432, '<code>sumFactorialDigits(75)</code> should return 432.');
- text: <code>sumFactorialDigits(100)</code> should return 648.
testString: assert.strictEqual(sumFactorialDigits(100), 648, '<code>sumFactorialDigits(100)</code> should return 648.');
Challenge Seed
function sumFactorialDigits(n) {
// Good luck!
return n;
}
sumFactorialDigits(100);
Solution
// solution required