freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/rosetta-code/factorial.chinese.md

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title id challengeType videoUrl localeTitle
Factorial 597b2b2a2702b44414742771 5 阶乘

Description

编写一个函数来返回一个数字的阶乘。

一个数字的因子由下式给出:

N = n *n-1*n-2* ..... * 1

例如3 = 3 * 2 * 1 = 6 4 = 4 * 3 * 2 * 1 = 24

注意0 = 1

Instructions

Tests

tests:
  - text: <code>factorial</code>是一种功能。
    testString: 'assert(typeof factorial === "function", "<code>factorial</code> is a function.");'
  - text: <code>factorial(2)</code>应该返回一个数字。
    testString: 'assert(typeof factorial(2) === "number", "<code>factorial(2)</code> should return a number.");'
  - text: <code>factorial(3)</code>应该返回6.“)
    testString: 'assert.equal(factorial(3),results[0],"<code>factorial(3)</code> should return 6.");'
  - text: <code>factorial(3)</code>应返回120.“)
    testString: 'assert.equal(factorial(5),results[1],"<code>factorial(3)</code> should return 120.");'
  - text: '<code>factorial(3)</code>应返回3,628,800。“'
    testString: 'assert.equal(factorial(10),results[2],"<code>factorial(3)</code> should return 3,628,800.");'

Challenge Seed

function factorial (n) {
  // Good luck!
}

After Test

console.info('after the test');

Solution

// solution required