61 lines
993 B
Markdown
61 lines
993 B
Markdown
---
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id: 5900f5201000cf542c510032
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challengeType: 5
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videoUrl: ''
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localeTitle: 问题435：斐波那契数的多项式
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---
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## Description
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<section id="description">
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斐波纳契数{fn，n≥0}被递归定义为fn = fn-1 + fn-2，基本情况为f0 = 0和f1 = 1。
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对于0≤i≤n，将多项式{Fn，n≥0}定义为Fn（x）= ∑fixi。
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例如，F7（x）= x + x2 + 2x3 + 3x4 + 5x5 + 8x6 + 13x7，而F7（11）= 268357683。
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令n =1015。求和[∑0≤x≤100 Fn（x）] mod 1307674368000（= 15！）。
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</section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>euler435()</code>252541322550。
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testString: assert.strictEqual(euler435(), 252541322550);
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function euler435() {
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// Good luck!
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return true;
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}
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euler435();
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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/section>
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