2.4 KiB
2.4 KiB
title | id | challengeType |
---|---|---|
Day of the week | 5966f99c45e8976909a85575 | 5 |
Description
A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task:
Write a function that takes a start year and an end year and return an array of all the years where the 25th of December will be a Sunday.
Instructions
Tests
tests:
- text: <code>findXmasSunday</code> is a function.
testString: assert(typeof findXmasSunday === 'function', '<code>findXmasSunday</code> is a function.');
- text: <code>findChristmasSunday(2000, 2100)</code> should return an array.
testString: assert(typeof findXmasSunday(2000, 2100) === 'object', '<code>findChristmasSunday(2000, 2100)</code> should return an array.');
- text: <code>findChristmasSunday(2008, 2121</code> should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]
testString: assert.deepEqual(findXmasSunday(1970, 2017), firstSolution, '<code>findChristmasSunday(2008, 2121</code> should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]');
- text: <code>findChristmasSunday(2008, 2121</code> should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
testString: assert.deepEqual(findXmasSunday(2008, 2121), secondSolution, '<code>findChristmasSunday(2008, 2121</code> should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]');
Challenge Seed
function findXmasSunday (start, end) {
// Good luck!
return true;
}
After Test
const firstSolution = [1977, 1983, 1988, 1994, 2005, 2011, 2016];
const secondSolution = [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118];
Solution
function findXmasSunday (start, end) {
const xmasSunday = [];
for (let year = start; year <= end; year++) {
const xmas = new Date(year, 11, 25);
if (xmas.getDay() === 0) {
xmasSunday.push(year);
}
}
return xmasSunday;
}