freeCodeCamp

1.9 KiB

Raw Blame History

id	title	challengeType	forumTopicId
587d7fb7367417b2b2512c0a	Create Many Records with model.create()	2	301537

Description

Sometimes you need to create many instances of your models, e.g. when seeding a database with initial data. Model.create() takes an array of objects like [{name: 'John', ...}, {...}, ...] as the first argument, and saves them all in the db.

Instructions

Modify the createManyPeople function to create many people using Model.create() with the argument arrayOfPeople.

Note: You can reuse the model you instantiated in the previous exercise.

Tests

tests:
  - text: Creating many db items at once should succeed
    testString: |
      getUserInput => $.ajax({url: getUserInput('url') + '/_api/create-many-people', type: 'POST', contentType: 'application/json', data: JSON.stringify([{name: 'John', age: 24, favoriteFoods: ['pizza', 'salad']}, {name: 'Mary', age: 21, favoriteFoods: ['onions', 'chicken']}])}).then(data => {
        assert.isArray(data, 'the response should be an array');
        assert.equal(data.length, 2, 'the response does not contain the expected number of items');
        assert.equal(data[0].name, 'John', 'The first item is not correct');
        assert.equal(data[0].__v, 0, 'The first item should be not previously edited');
        assert.equal(data[1].name, 'Mary', 'The second item is not correct');
        assert.equal(data[1].__v, 0, 'The second item should be not previously edited');
        }, xhr => { throw new Error(xhr.responseText); })

Challenge Seed

Solution

/**
  Backend challenges don't need solutions, 
  because they would need to be tested against a full working project. 
  Please check our contributing guidelines to learn more.
*/

1.9 KiB Raw Blame History