freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-an.../basic-javascript/compound-assignment-with-au...

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id title challengeType videoUrl localeTitle
56533eb9ac21ba0edf2244b1 Compound Assignment With Augmented Multiplication 1 具有增广乘法的复合赋值

Description

*=运算符将变量乘以数字。 myVar = myVar * 5;myVar乘以5 。这可以改写为: myVar *= 5;

Instructions

转换a bc的赋值以使用*=运算符。

Tests

tests:
  - text: <code>a</code>应该等于<code>25</code>
    testString: 'assert(a === 25, "<code>a</code> should equal <code>25</code>");'
  - text: <code>b</code>应该等于<code>36</code>
    testString: 'assert(b === 36, "<code>b</code> should equal <code>36</code>");'
  - text: <code>c</code>应该等于<code>46</code>
    testString: 'assert(c === 46, "<code>c</code> should equal <code>46</code>");'
  - text: 您应该为每个变量使用<code>*=</code>运算符
    testString: 'assert(code.match(/\*=/g).length === 3, "You should use the <code>*=</code> operator for each variable");'
  - text: 不要修改行上方的代码
    testString: 'assert(/var a = 5;/.test(code) && /var b = 12;/.test(code) && /var c = 4\.6;/.test(code), "Do not modify the code above the line");'

Challenge Seed

var a = 5;
var b = 12;
var c = 4.6;

// Only modify code below this line

a = a * 5;
b = 3 * b;
c = c * 10;

After Test

console.info('after the test');

Solution

// solution required