1.9 KiB
1.9 KiB
id | challengeType | title |
---|---|---|
5900f3761000cf542c50fe88 | 5 | Problem 9: Special Pythagorean triplet |
Description
a2 + b2 = c2
For example, 32 + 42 = 9 + 16 = 25 = 52.
There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc such that a + b + c = n
.
Instructions
Tests
tests:
- text: <code>specialPythagoreanTriplet(1000)</code> should return 31875000.
testString: assert.strictEqual(specialPythagoreanTriplet(1000), 31875000, '<code>specialPythagoreanTriplet(1000)</code> should return 31875000.');
- text: <code>specialPythagoreanTriplet(24)</code> should return 480.
testString: assert.strictEqual(specialPythagoreanTriplet(24), 480, '<code>specialPythagoreanTriplet(24)</code> should return 480.');
- text: <code>specialPythagoreanTriplet(120)</code> should return 49920.
testString: assert.strictEqual(specialPythagoreanTriplet(120), 49920, '<code>specialPythagoreanTriplet(120)</code> should return 49920.');
Challenge Seed
function specialPythagoreanTriplet(n) {
let sumOfabc = n;
// Good luck!
return true;
}
specialPythagoreanTriplet(1000);
Solution
const specialPythagoreanTriplet = (n)=>{
let sumOfabc = n;
let a,b,c;
for(a = 1; a<=sumOfabc/3; a++){
for(b = a+1; b<=sumOfabc/2; b++){
c = Math.sqrt(a*a+b*b);
if((a+b+c) == sumOfabc){
return a*b*c;
}
}
}
}