898 B
898 B
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5900f4291000cf542c50ff3b | Problem 188: The hyperexponentiation of a number | 5 | 301824 | problem-188-the-hyperexponentiation-of-a-number |
--description--
The hyperexponentiation or tetration of a number a
by a positive integer b
, denoted by a↑↑b
or {}^ba
, is recursively defined by:
a↑↑1 = a
,
a↑↑(k+1) = a^{(a↑↑k)}
.
Thus we have e.g. 3↑↑2 = 3^3 = 27
, hence 3↑↑3 = 3^{27} = 7625597484987
and 3↑↑4
is roughly {10}^{3.6383346400240996 \times {10}^{12}}
. Find the last 8 digits of 1777↑↑1855
.
--hints--
hyperexponentation()
should return 95962097
.
assert.strictEqual(hyperexponentation(), 95962097);
--seed--
--seed-contents--
function hyperexponentation() {
return true;
}
hyperexponentation();
--solutions--
// solution required