freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-1-multiples-of-3-an...

42 lines
791 B
Markdown
Raw Blame History

This file contains ambiguous Unicode characters!

This file contains ambiguous Unicode characters that may be confused with others in your current locale. If your use case is intentional and legitimate, you can safely ignore this warning. Use the Escape button to highlight these characters.

---
id: 5900f36e1000cf542c50fe80
title: 问题13和5的倍数
challengeType: 5
videoUrl: ''
---
# --description--
如果我们列出所有10以下是3或5的倍数的自然数我们会得到356和9。这些倍数的总和是23。
求出所有在`number`以下的3或5的倍数的总和。
# --hints--
`multiplesOf3and5(1000)`应该返回233168。
```js
assert.strictEqual(multiplesOf3and5(1000), 233168);
```
`multiplesOf3and5(49)`应该返回543。
```js
assert.strictEqual(multiplesOf3and5(49), 543);
```
`multiplesOf3and5(19564)`应该返回89301183。
```js
assert.strictEqual(multiplesOf3and5(19564), 89301183);
```
您的函数未使用我们的测试值返回正确的结果。
```js
assert.strictEqual(multiplesOf3and5(8456), 16687353);
```
# --solutions--